Write the following cubes in the expanded form : $(5 p-3 q)^{3}$

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Comparing the given expression with $(x-y)^{3},$ we find that

$x=5 p, \,y=3 q$

So, using Identity $VII$, we have :

$(5 p-3 q)^{3} =(5 p)^{3}-(3 q)^{3}-3(5 p)(3 q)(5 p-3 q) $

$=125 p^{3}-27 q^{3}-225 p^{2} q+135 p q^{2}$

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